Gibbs explorer

Slide ΔH, ΔS and the temperature and watch ΔG = ΔH − TΔS change as a straight line against temperature, with the spontaneous region shaded, the turn-over temperature T = ΔH/ΔS marked and the four sign cases sorted. A Class 12 level adds K = e^(−ΔG°/RT) and E° = −ΔG°/nF.

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  1. Reaction
  2. ΔH, ΔS, T
  3. ΔG line
  4. Spontaneous
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The four sign cases

ΔHΔSΔG = ΔH − TΔSSpontaneous?
−+always −Always
−−− when T is smallBelow ΔH/ΔS
++− when T is largeAbove ΔH/ΔS
+−always +Never

ΔH − means heat is given out; ΔS + means more disorder. In the "never" row, the reverse change is the spontaneous one. "Spontaneous" means the change can happen by itself at that temperature. It says nothing about speed: diamond turning into graphite has ΔG < 0 but takes longer than the age of the universe.

Try this

  • Ice melting: slide T across 273 K. ΔG changes sign right where ice and water are at equilibrium.
  • Ammonia: ΔG is negative at room temperature but turns positive above about 464 K. Why do factories still run hot? (Speed: look up the Haber process.)
  • Make ΔS zero. The line goes flat: temperature no longer matters.
  • Pick each row of the table by setting the signs of ΔH and ΔS. Which one can never go by itself?
  • Class 12: make ΔG° about −5.7 kJ/mol at 298 K. K comes out near 10. Every −5.7 kJ/mol multiplies K by ten.

Check yourself

Fresh numbers every time. Type a number or a fraction such as 3/4; nothing is saved or sent.

    What it shows

    Whether a change can happen by itself depends on two things: the heat it gives out or takes in (the enthalpy change ΔH) and how much more spread out, or disordered, things become (the entropy change ΔS). The Gibbs energy change puts them together: ΔG = ΔH − TΔS. When ΔG is negative the change is spontaneous at that temperature; when it is positive, it is not (the reverse change is); when it is zero, the system is at equilibrium.

    Because ΔH and ΔS hardly change with temperature, ΔG plotted against T is a straight line: it starts at ΔH when T = 0 and slopes by −ΔS. Where the line crosses zero, at T = ΔH/ΔS, the reaction turns over from one side to the other. This page draws that line, shades the spontaneous region green, and sorts every reaction into one of four sign cases.

    It follows thermodynamics in Class 11 chemistry, and its Class 12 level links to equilibrium and electrochemistry. The thermochemistry calculator works out ΔH, ΔS and ΔG for any reaction you type; the le Chatelier sandbox sandbox shows what temperature does to an equilibrium; and the galvanic cell builder builder turns ΔG into a cell voltage.

    How to use it

    1. Start from a reaction: ice melting, making ammonia, heating limestone, hydrogen peroxide breaking down, or making ozone. Their ΔH and ΔS are rounded values for the equation as written. Pick My own numbers to type anything.
    2. Slide ΔH, ΔS and T, or type them in the boxes. ΔH is in kJ/mol; ΔS is in J/(K·mol), so it is divided by 1000 before it is multiplied by T. The formula line shows each step with your numbers.
    3. Read the picture. The blue line is ΔG at every temperature from 0 to 1500 K; the big dot is your temperature; the orange dot is the turn-over temperature.
    4. The table of four sign cases lights up the row your reaction belongs to.
    5. Class 12 level adds the equilibrium constant K = e^(−ΔG°/RT) and the cell voltage E° = −ΔG°/(nF) for n electrons moved.

    Worked example

    Making ammonia, N₂ + 3H₂ → 2NH₃, has ΔH = −92.2 kJ/mol and ΔS = −198.7 J/(K·mol). At 298 K:

    ΔG = −92.2 − 298 × (−0.1987) = −92.2 + 59.21 = −32.99 kJ/mol, so it is spontaneous.

    Both signs are negative, so it is the “spontaneous when cold” case. It turns over at T = ΔH/ΔS = −92 200 ÷ −198.7 = 464.0 K (about 191 °C). At the Class 12 level, K = e^(32 987 ÷ (8.314 × 298)) ≈ 6.05 × 10⁵.

    For ice, ΔH = +6.01 kJ/mol and ΔS = +22.0 J/(K·mol): T = 6010 ÷ 22.0 = 273.2 K, the melting point. Below it ΔG is positive (ice stays ice); above it, negative (ice melts).

    The four cases in one line each

    • ΔH negative, ΔS positive: spontaneous at every temperature.
    • ΔH positive, ΔS negative: never spontaneous; the reverse change is.
    • Both negative: spontaneous below T = ΔH/ΔS.
    • Both positive: spontaneous above T = ΔH/ΔS.

    Check yourself

    Four questions with fresh numbers: ΔG at a temperature, the temperature where a change becomes spontaneous, which sign case applies, and K from ΔG°. Nothing is saved.

    FAQ

    Why divide ΔS by 1000? ΔH is in kilojoules but ΔS is usually given in joules per kelvin. Mixing them is the most common slip.

    Does negative ΔG mean the reaction is fast? No. ΔG says whether a change can go, not how quickly. That is kinetics.

    Is this from my textbook? It covers the standard school topic with its own examples and pictures. It is an independent study aid, not part of NCERT.

    Where the numbers come from

    • Standard thermodynamics: ΔG = ΔH − TΔS, ΔG° = −RT ln K and ΔG° = −nFE°. R and F from CODATA 2018. Preset ΔH and ΔS values are rounded general reference values, labelled as rounded. Written for fibub; no textbook text, figures or exercises are used.
    • Checked against values worked by hand in independent Python: ice melting (T = 273.18 K), ammonia synthesis (ΔG at 298 K = −32.99 kJ/mol, K ≈ 6.05 × 10⁵, turn-over 464.0 K) and limestone decomposing (turn-over 1110.9 K).

    Standard scientific values, such as constants, atomic weights and melting points, are facts found in every textbook; we name where ours were checked. If you are an author or publisher and want a value, a credit or a table changed or removed, tell us and we will act quickly.

    Last updated 2026-11-09.

    Change log for Gibbs explorer

    1. Add #1361 ΔG = ΔH − TΔS explorer Details on GitHub

    Every change to fibub

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